This was repeated until the mass remained constant, indicating all solvent had been removed.   Terms. The titanium atom then undergoes an intramolecular nucleophilic attack by Oxygen #2 of the TBHP. One week later, the flask was removed from the freezer and immediately placed in a -23O C acetone and dry ice bath. © 2008-2020 ResearchGate GmbH. Although the experiment did not involve the determination of which peak corresponded to each specific enantiomer, literature precedence asserts that the mCPBA epoxidation procedure did not favor a specific enantiomer, whereas the Sharpless Asymmetric Epoxidation favored the (2S, 3S)-epoxy geraniol isomer.1. The first two were inaccurate in showing proper. Epoxidation Of Trans-Anethole CH3 CH3 MCPBA CH2C2. Fractions 6-10 were combined and concentrated to dryness to yield a clear colorless oil. How to determine Hammett plot ? *��X��J�~�S*X8kC�ݷ���|3) L-(+)-Diethyltartrate (671 mg, 3.25 mmol, 1 equiv) was weighed directly into a dry 25 mL round-bottom flask equipped with a magnetic stir bar. The organic layer was then washed twice with equal volumes of water, dried over anhydrous sodium sulfate (Na2SO4), and concentrated to dryness to yield a cloudy colorless oil. Fractions 5-7 were combined and concentrated to dryness to yield a clear colorless oil. © 2003-2020 Chegg Inc. All rights reserved. Ed. Then to obtain my cpd (benzoylated sugar) I just worked up (water/ethyl acetate) the organic layer containing my cpd. Ed. In terms of a “real-world” application, the stereoselective and regioselective properties of the Sharpless Asymmetric Epoxidation are particularly useful in the enantioselective synthesis of various compounds. Prepare a solution of 0.28 g mCPBA in 3.0 mL of dichloromethane. The purpose of this experiment is to compare two epoxidation procedures—a standard epoxidation procedure that uses meta-chloroperoxybenzoic acid (mCPBA) and the Sharpless Asymmetric Epoxidation reaction.1,2 The enantioselectivity of each epoxidation reaction will be examined via chiral lanthanide shift reagents and 1H-NMR spectroscopy. Procedure and Observations: Refer to the procedure in the lab manual, page 2. Add KI aqueous solution and extract with ethyl acetate, the solution will turn into dark red. The purpose of this experiment was to investigate the enantioselectivity of two epoxidation procedures.1,2 The epoxidation of geraniol using the mCPBA epoxidation procedure and the Sharpless Asymmetric Epoxidation was studied in detail. All rights reserved. Once the desired epoxy acetate product was isolated, the enantiomeric ratio of each product was determined using chiral shift 1H-NMR spectroscopy. The larger integration value was divided by the smaller integration value to yield the enantiomeric ratio.1,2 The enantiomeric excess was then easily determined from these integration values by finding the sum of the integration values and determining the percentage of each enantiomer present. The vial was capped immediately and labeled “Chiral Shift Reagent.”. The L isomer facilitates the delivery of Oxygen #1 to the Re face of the allylic alcohol, whereas the D isomer facilitates the delivery of Oxygen #1 to the Si face of the allylic alcohol.5 Figure 5 shows the Re and Si attack of an allylic alcohol. Dry the organic layer over anhydrous NaSO, and filter into a tared, dry 25-mL. This coordination places the position 2,3 alkene in close proximity to the Ti(OiPr)4/L-(+)-DET complex, and ultimately, the complex has a “directing effect” that facilitates the delivery of the peroxide oxygen to the bottom face of the position 2,3 alkene. All rights reserved. The reaction mixture was stirred for five min. -��Y�xg����j�PKw O��A4C^���:�!g����읻і�Aaх�4��B ���#-����[`����/SA�삉}�/���u���O֔�UTB�3�ab2Ry�*-;�����=:Gf�D�4�i� �i�u���c!P%E��!%���xO��{?�y��2M������ê�8��uO4+����K$���~ῃ���I>��Dn����= ��2+)+q->|9��]"�h?%[��v����h�]ۡG��K5�J��G��9��Ȇ3j�ix�}2�=R0g�[ �;��eJp(|�v��ݰ��P0{R$��8Q�z�:������TC�3���p2��ڭji��v������w�?�à�g��ߩ��y�;oT��-�����?����r�P�i����w�갑�k7�]3�v��)$]+����P�B��u��ky� )�jĹ˲16��2�"��h;�k�c�јu��p����-���Ƃ��(wj�qg�V�-�Z��q���,�AN��聿C��~��0j��C�b�8o��;ql��j�2w/�^(z�U��M�>o��TBž�j�������CV�O���J�kd ��3rD�^�z#Va`�ڝ���}+�� This induces Oxygen #1 to give its electrons to the neighboring positively charged Oxygen #2.

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